Gravity and Gravitation — 50 MCQs
Comprehensive 50-question MCQ set on gravitational field, orbital motion, escape velocity, satellite dynamics and planetary phenomena (arranged easy to very hard).
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1. According to Newton's law of gravitation, the gravitational force between two point masses is inversely proportional to:
easyExplanation: Newton's law of gravitation states F ∝ 1/r², where r is the distance between the masses. -
2. The SI value of the universal gravitational constant G is approximately:
easyExplanation: G = 6.674 × 10⁻¹¹ N m² kg⁻² is a fundamental physical constant. -
3. The gravitational force between two masses is always:
easyExplanation: Gravity is always attractive; it pulls masses together. -
4. The SI unit of gravitational field strength is:
easyExplanation: Gravitational field strength is force per unit mass: N kg⁻¹ or m s⁻². -
5. The relation connecting acceleration due to gravity g, the universal gravitational constant G, the mass of the Earth M, and its radius R is:
easyExplanation: At Earth's surface, the gravitational field strength is g = GM/R². -
6. The SI unit of gravitational potential is:
easyExplanation: Gravitational potential is potential energy per unit mass: J kg⁻¹. -
7. The gravitational potential energy of a bound two-mass system is always:
easyExplanation: For a bound system with potential energy zero at infinity, gravitational PE is always negative. -
8. As altitude above the Earth's surface increases, the value of g:
easyExplanation: g decreases with altitude as g_h = GM/(R+h)², so larger h gives smaller g. -
9. As depth below the Earth's surface increases, the value of g:
easyExplanation: For uniform density, only the enclosed mass contributes, so g decreases linearly with depth. -
10. At the exact centre of the Earth, the value of g is:
easyExplanation: By symmetry, the net gravitational field from all surrounding mass is zero at the centre. -
11. The centre of mass of a system of particles depends only on:
easyExplanation: Centre of mass depends only on the mass distribution, not on external fields. -
12. The centre of gravity of a body depends on:
easyExplanation: Centre of gravity depends on both mass distribution and gravitational field strength. -
13. The orbital velocity of a satellite in a circular orbit of radius r around a planet of mass M is given by:
easyExplanation: For circular orbit, centripetal force equals gravitational force: mv²/r = GMm/r², giving v = √(GM/r). -
14. The escape velocity from a planet's surface, expressed in terms of g and R, is:
easyExplanation: From energy conservation, v_e = √(2GM/R) = √(2gR). -
15. For a satellite to be geostationary, its time period must equal:
easyExplanation: A geostationary satellite orbits once per Earth rotation, so T = 24 hours. -
16. The value of the universal gravitational constant G was first experimentally determined by:
mediumExplanation: Henry Cavendish measured G using a torsion balance in 1798. -
17. If the distance between two point masses is doubled, the gravitational force between them becomes:
mediumExplanation: Force is inversely proportional to r², so doubling r makes F become F/4. -
18. If both masses in a gravitating pair are doubled and the distance between them is halved, the new gravitational force is how many times the original?
mediumExplanation: F ∝ m₁m₂/r². New F ∝ (2m₁)(2m₂)/(r/2)² = 4m₁m₂/(r²/4) = 16(m₁m₂/r²), so 16 times. -
19. The gravitational field strength at a distance of 2R from the centre of a planet of radius R (surface gravity g) is:
mediumExplanation: E ∝ 1/r². At 2R, the field is E = g/4. -
20. The value of g at a height equal to the Earth's radius R above the surface (i.e. at a distance 2R from the centre) is:
mediumExplanation: At distance 2R from centre, g_h = GM/(2R)² = GM/(4R²) = g/4. -
21. The value of g at a depth of R/2 below the Earth's surface (uniform-density approximation) is:
mediumExplanation: For uniform density, g(d) = g(1 - d/R). At d = R/2, g = g/2. -
22. The ratio of escape velocity to orbital velocity at the same radius is:
mediumExplanation: v_e = √(2GM/r) and v_o = √(GM/r), so v_e/v_o = √2. -
23. If the orbital radius of a satellite is increased to 4 times its original value, its orbital velocity becomes:
mediumExplanation: v ∝ 1/√r, so if r becomes 4r, v becomes v/2. -
24. If the orbital radius of a satellite is increased to 4 times its original value, its time period becomes:
mediumExplanation: T ∝ r^(3/2), so if r becomes 4r, T becomes (4)^(3/2) = 8 times. -
25. If the orbital radius of a satellite is doubled, its kinetic energy becomes:
mediumExplanation: KE = GMm/(2r), so if r doubles, KE becomes half. -
26. If the orbital radius of a satellite is doubled, the magnitude of its potential energy becomes:
mediumExplanation: PE = -GMm/r, so magnitude is GMm/r. If r doubles, magnitude becomes half. -
27. The total mechanical energy E of an orbiting satellite is related to its kinetic energy KE by:
mediumExplanation: Total energy E = KE + PE = GMm/(2r) - GMm/r = -GMm/(2r) = -KE. -
28. The binding energy of a satellite of mass m orbiting at radius r around a planet of mass M is given by:
mediumExplanation: Binding energy is the magnitude of total energy: BE = GMm/(2r). -
29. The approximate height of a geostationary orbit above the Earth's surface is:
mediumExplanation: Geostationary orbit altitude is approximately 35,786 km above Earth's surface. -
30. The approximate orbital period of a typical GPS satellite is:
mediumExplanation: GPS satellites orbit at about 20,200 km altitude with a period of approximately 12 hours. -
31. The minimum number of GPS satellites a receiver must detect simultaneously to determine its full three-dimensional position and correct its own clock is:
mediumExplanation: Four satellites are needed: three for 3D position and one to correct the receiver's clock. -
32. The centre of mass and centre of gravity of a body coincide when:
mediumExplanation: When the gravitational field is uniform, centre of gravity and centre of mass are the same. -
33. In the vector form of Newton's law of gravitation, the negative sign indicates that the force is:
mediumExplanation: The negative sign in F = -GMm/r² indicates the force is attractive. -
34. The approximate escape velocity from the Earth's surface is:
mediumExplanation: Earth's escape velocity is approximately 11.2 km/s. -
35. The gravitational potential at an infinite distance from any mass is taken to be:
mediumExplanation: Gravitational potential is conventionally defined as zero at infinity. -
36. Two satellites orbit the same planet at radii r and 4r respectively. The ratio of their time periods T(4r):T(r) is:
hardExplanation: T ∝ r^(3/2), so T(4r)/T(r) = (4r/r)^(3/2) = 4^(3/2) = 8. -
37. A satellite's orbital radius is reduced to half its original value. Its orbital velocity:
hardExplanation: v ∝ 1/√r, so v(r/2) = v√2, an increase by factor √2. -
38. Two planets have the same average density but different radii R₁ and R₂. The ratio of their surface gravitational accelerations g₁:g₂ is:
hardExplanation: g = (4/3)πGρR, so for equal density, g ∝ R, giving g₁:g₂ = R₁:R₂. -
39. If the Earth's radius were halved while its mass remained unchanged, the new surface value of g would become:
hardExplanation: g = GM/R², so if R becomes R/2, g becomes GM/(R/2)² = 4GM/R² = 4g. -
40. A hypothetical planet has twice the mass and twice the radius of Earth. Compared to Earth's escape velocity vₑ, the escape velocity from this planet's surface is:
hardExplanation: vₑ = √(2GM/R). For 2M and 2R: vₑ' = √(2G(2M)/(2R)) = √(2GM/R) = vₑ. -
41. Two identical point masses m are fixed at the two ends of a light rod of length d. A third mass is placed exactly at the midpoint of the rod. The net gravitational force on the third mass due to the two end masses is:
hardExplanation: By symmetry, the two equal forces pull in opposite directions and cancel exactly. -
42. The energy that must be supplied to raise a satellite of mass m from a circular orbit of radius r to a circular orbit of radius 2r, around a planet of mass M, is:
hardExplanation: ΔE = E(2r) - E(r) = [-GMm/(2·2r)] - [-GMm/(2r)] = -GMm/4r + GMm/2r = GMm/4r. -
43. Using the formula for variation of g with depth, the depth below the Earth's surface at which g reduces to exactly half its surface value is:
hardExplanation: g(d) = g(1 - d/R) = g/2 gives 1 - d/R = 1/2, so d = R/2. -
44. Using the exact (non-approximated) expression for variation of g with altitude, the height above the Earth's surface at which g reduces to exactly one-fourth of its surface value is:
hardExplanation: g_h/g = 1/(1+h/R)² = 1/4 gives 1+h/R = 2, so h = R. -
45. A satellite orbits a planet of mass M at radius r with time period T. An identical satellite orbits a different planet of mass 4M at the same orbital radius r. Its time period will be:
hardExplanation: T² = 4π²r³/(GM), so T ∝ 1/√M. For 4M: T' = T/√4 = T/2. -
46. Regarding the relativistic time corrections applied to GPS satellite clocks, which statement is correct?
hardExplanation: General relativistic effect (weaker field at altitude) makes clocks run faster; special relativistic effect (orbital speed) makes them run slower. General effect dominates. -
47. If the mass of a planet is doubled while a satellite's orbital radius r is kept unchanged, the satellite's new orbital velocity becomes:
hardExplanation: v = √(GM/r), so if M doubles, v becomes √(2GM/r) = √2 · v. -
48. A satellite is placed in a circular equatorial orbit at a radius smaller than the geostationary radius, moving in the same direction as the Earth's rotation. Relative to a fixed point on the Earth's surface, this satellite will appear to:
hardExplanation: Smaller radius means shorter period, so the satellite orbits faster than Earth rotates, drifting eastward. -
49. As the orbital radius r of a satellite decreases, its binding energy:
hardExplanation: Binding energy BE = GMm/(2r). As r decreases, BE increases (becomes more positive). -
50. A hypothetical planet has twice the mass of Earth and half the radius of Earth. The escape velocity from this planet's surface, compared to Earth's escape velocity vₑ, is:
hardExplanation: vₑ' = √(2GM'/R') = √(2G(2M)/(R/2)) = √(4·2GM/R) = 2·√(2GM/R) = 2vₑ.